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Esercizi Gasdinamica

Politecnico di Torino Ingegneria Aerospaziale 2022
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It seems you've provided a series of quiz questions and solutions related to fluid dynamics, specifically focusing on compressible flow and heat transfer. The questions cover topics such as adiabatic walls, turbulence effects, and the behavior of gases in supersonic flows. Here's a structured summary of the key points: ### Quiz Questions 1. **Fluid Dynamics Basics** - Questions about continuity, energy, and momentum equations. 2. **Adiabatic Walls** - Calculations involving temperature changes across adiabatic walls. 3. **Turbulence Effects** - Determining the effects of turbulence on flow characteristics and heat transfer coefficients.
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Let's go through the provided problems step-by-step to ensure a thorough understanding and correct solutions. ### Problem 1: Compressible Flow in a Converging Diverging Nozzle **Given:** - \( M_1 = 2 \) - \( d_1 = 0.8 \, \text{m} \) - \( L = 0.5 \, \text{m} \) **Required:** - Determine the exit Mach number \( M_2 \) and the pressure ratio \( P_2/P_1 \). **Solution:** 1. **Mach Number at Exit (\( M_2 \)):** - For a converging-diverging nozzle, if \( d_1 > 0 \), it is a subsonic flow. - Using the area-Mach number relation for subsonic flow: \[ \frac{d}{d_1} = \left( \frac{2}{\gamma + 1} \right)^{\frac{\gamma + 1}{2(\gamma - 1)}} M^2 \] - Given \( d > d_1 \), the flow is subsonic, and we can use: \[ M_2 = \sqrt{\left( \frac{2}{\gamma + 1} \right)^{\frac{\gamma + 1}{2(\gamma - 1)}} \left( \frac{d}{d_1} \right)^2} \] - For air, \( \gamma = 1.4 \): \[ M_2 = \sqrt{\left( \frac{2}{1.4 + 1} \right)^{\frac{1.4 + 1}{2(1.4 - 1)}} \left( \frac{0.8}{d_1} \right)^2} \] - Assuming \( d_1 = 1 \, \text{m} \): \[ M_2 = \sqrt{\left( \frac{2}{2.4} \right)^{\frac{2.4}{0.8}} \left( 0.8 \right)^2} \] - Simplifying: \[ M_2 \approx 1 \] 2. **Pressure Ratio (\( P_2/P_1 \)):** - For subsonic flow in a converging-diverging nozzle, the pressure ratio can be found using the isentropic relations: \[ \frac{P_2}{P_1} = \left( 1 + \frac{\gamma - 1}{2} M_1^2 \right)^{-\frac{\gamma}{\gamma - 1}} \] - Substituting \( M_1 = 2 \) and \( \gamma = 1.4 \): \[ \frac{P_2}{P_1} = \left( 1 + \frac{1.4 - 1}{2} \cdot 2^2 \right)^{-\frac{1.4}{0.4}} = \left( 1 + 1.8 \right)^{-3.5} = (2.8)^{-3.5} \] - Calculating: \[ P_2/P_1 \approx 0.16 \] **Final Answers:** - \( M_2 \approx 1 \) - \( P_2/P_1 \approx 0.16 \) ### Problem 2: Heat Transfer in a Converging Diverging Nozzle **Given:** - \( d = 2 \, \text{m} \) - \( L = 0.5 \, \text{m} \) - \( M_1 = 2 \) - \( Q_m = 8000 \, \text{W/m}^2 \) **Required:** - Determine the exit Mach number and the pressure ratio. **Solution:** 1. **Mach Number at Exit (\( M_2 \)):** - Similar to Problem 1, for \( d > d_1

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